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[Solved]: Height and depth of every node in Path Compression

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Problem Detail: 

If we have an union-find(disjoint-set) data structure and we are doing an union by rank and path compression for a find operation, how would the depth and height of every node change after the find operation?

I am trying to find the amortized cost of the find operation using the potential function:

$$phi(x) = \sum_{x} height(x) $$

I know this is not the right potential function, however, i am trying to learn more about amortized analysis and i am just practicing by analyzing more data structures.

Asked By : karthik ramesh

Answered By : NP-hard

I assume that the height of a node $\small x$, denoted as $\small h(x)$, is recursively defined as: $$ \small h(x) = \begin{cases} 0 & \text{ if $x$ is a leaf} \\ 1+\max\{h(y) \mid y\text{ is child of } x\} & \text{ otherwise } \end{cases} $$ Let the value of the potential function before calling $\small \texttt{Find}(x)$ be $\small \Phi$ and the value after the call be $\small \bar{\Phi}$. Similarly we can define $\small h(x)$ and $\small \bar{h}(x)$ respectively. Denote as $\small P_x$ the path from $\small x$ to the root $\small r$ of the corresponding tree. By path compression, nodes in $\small P_x$ (except $\small r$) are all set to point to $\small r$. Therefore, generally $\small \bar{h}(y) \leq h(y)$ for $\small y \in P_x$, since $\small y$ may have one child removed.

The amortized cost of $\small \texttt{Find}(x)$ is: $$ \small \mathcal{O}(|P_x|) + \bar{\Phi} - {\Phi} = \mathcal{O}(|P_x|) + \sum_{y \in P_x}\{\bar h(y) - {h}(y)\} $$ where $\small |P_x|$ is the # of nodes in $\small P_x$ and $\small \mathcal{O}(|P_x|)$ is the actual cost of $\small \texttt{Find}(x)$. Now look at term $\small \bar h(y) - {h}(y)$, by the discussion above, its value is no greater than $\small 0$. Unfortunately, there are special cases where $\small \bar h(y) = h(y)$ for all $\small y \in P_x$. Therefore, what we can say about the amortized cost, using sum of heights as potential function, is the amortized cost is $\small \mathcal{O}(|P_x|)$, which is the same as the worse-case bound.

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Question Source : http://cs.stackexchange.com/questions/64589

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