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Prove an arithmetic property of a partial recursive function

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Problem Detail: 

I have this program written in haskell : enter image description here

I have to prove that: $(\forall a \in \mathbb{N})[!D_V [h](a) \Rightarrow log_2 (D_V[h](a) )\equiv 2 (mod$ $ 10) ]$.

The predicate $P_2$ for the $g$ function is obvious : $P_2(f,g) \equiv (\forall x,y \in \mathbb{N})[!g(x,y) \Rightarrow g(x,y)\backsimeq xy]$.

But the predicate for the function $f$ which would give me authomaticaly the one for $h$ I have no idea what it should be.

Any ideas and help in solving this problem is welcomed :)

Notations:

  • $D_V[h]$: denotational semantics with passing by value of the function $f$.
  • $!F(x)$ means that $F$ is defined at point $x$.
  • $F(x) \backsimeq V$ means has the value $V$ at the point $x$ or is undefined.
Asked By : user3719857

Answered By : Yuval Filmus

The function $f$ computes the recurrence relation $$ f(x) = \begin{cases} 4 & x \leq 1, \\ f(x-1)^2 f(x-2)^4 & x > 1. \end{cases} $$ Taking $\ell = \log_2 \circ f$, we get $$ \ell(x) = \begin{cases} 2 & x \leq 1, \\ 2\ell(x-1) + 4\ell(x-2) & x > 1. \end{cases} $$ Now, modulo 10 we have $$ 2 \cdot 2 + 4 \cdot 2 = 12 \equiv 2 \pmod{10}. $$ An easy proof by induction then shows that $\ell(x) \equiv 2 \pmod{10}$ for all $x$.

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Question Source : http://cs.stackexchange.com/questions/51725

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