Cheap and Secure Web Hosting Provider : See Now

[Answers] One-time-pad possible solutions

, , No Comments
Problem Detail: 

I am having a very difficult time trying to understand what exactly this question is asking.

How many valid English plaintexts are there for the ciphertext message CJU using a length-3, one-time pad of cyclic shifts, (i, j, k)?

If the encrypted question message is CJU and the one time pad is i, j, k would there not be exactly 1 solution? We are given the one time pad i, j, k so we can derive the plaintext simply by some alagebra

(x + 9) % 26 = 3

(y + 10) % 26 = 10

(z + 11) % 26 = 21

Where x, y, and z are the plaintext letters T, Z, J?

I feel like this is a trick question that I am not understanding

Asked By : Programatic

Answered By : David Richerby

$(i,j,k)$ is not a specific OPT. It's three variable names that you can use to talk about the key. The question is just asking, "Given all possible three-character OTPs, how many valid English plaintexts are there for the ciphertext CJU?"

In other words, how many different values are there for the triple $(i,j,k)$ such that "CJU" decrypts to an actual English word.

Best Answer from StackOverflow

Question Source :

3.2K people like this

 Download Related Notes/Documents


Post a Comment

Let us know your responses and feedback