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[Answers] NFA to accept strings where the third AND the third-last element are b

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Problem Detail: 

Alphabet is {a,b}, the third element from the start must be "b" (e.g: aab..., abb...) and the third-last element must also be "b" (e.g: ...baa, ...bbb). I can do them separately but at the same time I don't know where to start. Help please.

Asked By : Marx Guimarães

Answered By : J.-E. Pin

Hint. If $A$ is the alphabet, a regular expression for your language is $AAbA^*bAA \cup AAbAA \cup AbbA \cup bAb$.

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Question Source : http://cs.stackexchange.com/questions/57926

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