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[Solved]: How to purge a linked list in $\mathcal{O}(n\log n)$ time?

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Problem Detail: 

I was wondering how to remove duplicate values from a linked list in $\mathcal{O}(n\lg n)$ time. I have an idea that by using merge sort when we want to compare elements for choosing the small one, if they are equal advance on pointer and just consider one element. Any alternatives?

Asked By : Hadi Amiri

Answered By : Anton

  1. Sort the linked list in $O(n \log n)$ time.
  2. Go through each element of the list in their order and remove the element, if it is the same as the previous one in $O(n)$ time.

The total complexity is $O(n \log n)$, which is what you are searching for.

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